pytho中oct的用法(pythooctave)

导语：一日一技：Python中内置的oct() 函数

oct（）函数是Python3中的内置方法之一。 oct（）方法采用整数，并以字符串格式返回其八进制表示形式。

oct()语法如下：

Syntax : oct(x) 参数x – Must be an integer number and can be in either binary, decimal or hexadecimal format.返回值的八进制表示形式。Errors and Exceptions :   TypeError：当将整数类型常量以外的任何内容作为参数传递时，返回TypeError。

代码＃1：说明oct（）函数的用法

print(&34; + oct(23)) print(&34;&39;z&34; + oct(ord(&39;))) print(&34;&34; + oct(0b10111)) print(&34;&34; + oct(0x17)) 

输出：

The octal representation of 23 is 0o27The octal representation of the ascii value of &39; is 0o172The octal representation of the binary of 23 is 0o27The octal representation of the binary of 23 is 0o27

代码2：展示TypeError异常错误

print(&34; + oct(29.5)) 

输出报错信息：

Traceback (most recent call last):  File &34;, line 3, in     print(&34;+oct(29.5))TypeError: &39; object cannot be interpreted as an integer

应用范围：

oct（）用于所有类型的标准转换。 例如，从十进制转换为八进制，从二进制转换为八进制，从十六进制转换为八进制.

代码3：实例如下

print(&34;) print(&34;) print(&34;) def  bin_to_oct(): print(&34;) x = int(input(), 2) print(&34; + str(x) + &34; + oct(x) ) def hex_to_oct(): print(&34;) x = int(input(), 16) print(&34; + str(x) + &34; + oct(x)) def decimal_to_oct(): print(&34;) x = int(input()) print(&34; + str(x) + &34; + oct(x)) ch = input(&34;) if ch is &39;: hex_to_oct() elif ch is &39;: decimal_to_oct() elif ch is &39;: bin_to_oct() 

输出：

a. Hexadecimal to Octal b. Decimal to Octalc. Binary to OctalEnter your choice :-aEnter your input in HEX format :-0x13Octal form of 19 is 0o23

a. Hexadecimal to Octal b. Decimal to Octalc. Binary to OctalEnter your choice :-bEnter a number with base-10 format :-123Octal form of 123 is 0o173

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